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๐Ÿ“ฐ Verizon Redwood Falls ๐Ÿ“ฐ Destin Verizon ๐Ÿ“ฐ Verizon Johnson City Ny ๐Ÿ“ฐ Solution Solve 2Z 60Circ 120Circ 420Circ 480Circ Within 0Circ 720Circ Yielding ๐Ÿ“ฐ Solution Sum The Expressions 4Y 3 2Y 5 Y 7 7Y 9 Divide By 3 And Set Equal To 10 Frac7Y 93 10 Multiply Both Sides By 3 7Y 9 30 Subtract 9 7Y 21 Divide By 7 Y Boxed3 ๐Ÿ“ฐ Solution The Altitude Is Modeled By The Quadratic Function Y 3X2 12X 15 Since The Coefficient Of X2 Is Positive The Parabola Opens Upward And The Minimum Value Occurs At The Vertex The X Coordinate Of The Vertex Is ๐Ÿ“ฐ Solution The Area A Of A Regular Hexagon With Side Length S Is Given By The Formula A Frac3Sqrt32S2 Setting This Equal To 54Sqrt3 We Have ๐Ÿ“ฐ Solution The Area A Of The Triangle Is Given By ๐Ÿ“ฐ Solution The Arithmetic Mean Is Calculated By Summing The Values And Dividing By The Count Frac10 14 163 Frac403 Approx 13Overline3 The Exact Average Is Boxeddfrac403 ๐Ÿ“ฐ Solution The Cosine Function Oscillates Between 1 And 1 So 5Cosleftfracpi6Xright Ranges From 5 To 5 Adding 10 Shifts The Range To 5 15 The Range Is Boxed5 15 ๐Ÿ“ฐ Solution The Expression Under The Square Root Must Satisfy 4 X2 Geq 0 So X In 2 2 The Maximum Value Of Sqrt4 X2 Is 2 At X 0 And The Minimum Is 0 At X Pm 2 The Range Is Boxed0 2 Think ๐Ÿ“ฐ Solution The Function Ht 5T2 30T 10 Is A Quadratic With A Negative Leading Coefficient So The Maximum Occurs At The Vertex The Time T At Which The Maximum Altitude Occurs Is ๐Ÿ“ฐ Solution The Minimum Depth Where Both Measurements Coincide Is The Lcm Of 5 And 7 Since 5 And 7 Are Prime Lcm5 7 5 Cdot 7 35 The Answer Is Boxed35 ๐Ÿ“ฐ Solution The Slope Of The Line From 2 3 To 5 11 Is Frac11 35 2 Frac83 Since Tan Theta Equals The Slope Tan Theta Frac83 Boxeddfrac83 ๐Ÿ“ฐ Solution The Volume V Of A Cone Is Given By ๐Ÿ“ฐ Solution To Divide Both 48 And 72 Regions Into Equal Sized Groups With No Regions Left Out We Must Find The Greatest Common Divisor Gcd Of 48 And 72 ๐Ÿ“ฐ Solution To Find The Least Common Multiple Lcm Of 12 And 18 Factorize Both 12 22 Cdot 3 And 18 2 Cdot 32 The Lcm Takes The Highest Powers Of All Primes 22 Cdot 32 4 Cdot 9 36 Thus The Lcm Is Boxed36 ๐Ÿ“ฐ Solution To Find The Smallest Number Of Samples Per Column Such That The Number Of Columns Is A Multiple Of Both 6 And 10 We Compute The Least Common Multiple Lcm Of 6 And 10